Why does "%d" in str$ print zero?

[lyizb]

wlog int(1234.5),str$(int(1234.5),"%5d"),str$(int(1234.5),"%5u")

Yields: 1234 0 0

How do I print an integer right-justified within a fixed number of characters?

(If it makes a difference, this is with a C3SuperMini.)

Also, the spacing in the documentation seems to imply that wlog "|"+str$(15,"%4.3f")+"|" would be printed with two spaces before the 15.000, but I get |15.000|.

[bugs]

I think you need the additional ",!" for integers...

Code: [Local Link Removed for Guests]

wlog int(12345.6),str$(int(12345.6),"%5d",1),str$(int(1234.5),"%5u",1)

[lyizb]

I think you need the additional ",!" for integers...

That works, thanks, but I can't say I understand why it should be necessary, since "%d" and "%u" imply integers, and the int() should be converting the numbers to integers.

[cicciocb]

I think you need the additional ",!" for integers...

That works, thanks, but I can't say I understand why it should be necessary, since "%d" and "%u" imply integers, and the int() should be converting the numbers to integers.

This is required because the internal printf() C-function need to know the format of the value to be converted (in annex all the variables are floating point)